# digitizer.py - functionality for producing vertical strings
# of digits.  Here is a gallery:
#    0000    1   22222 33333   44  55555 66666 77777 88888  9999
#   00  00  11       2     3  4 4  5     6        7  8   8 9   9
#   00  00   1   22222 33333 44444 55555 66666   7   88888  9999
#   00  00   1   2         3    4      5 6   6  7    8   8    9
#    0000  11111 22222 33333    4  55555 66666 7     88888 999

def toString(n):
    # First, we need to create a list of digit values.
    # Then, we call a function that actually creates
    # strings for individual digits.  We need to return
    # whole string of potentially several digits.
    # Notice the order of concatenation!
    
    s = ""
    while n > 0:
        print "Next digit to process is " + str(n%10)
        s = getDigit(n % 10) + s
        n /= 10
    return s + ":)"
    
def getDigit(d):
    if d == 0:
        return " 0000 \n00  00\n00  00\n00  00\n 0000\n\n"
    elif d == 1:
        return "  1  \n 11  \n  1  \n  1  \n11111\n\n"
    elif d == 2:
        return "22222\n    2\n22222\n2    \n22222\n\n"
    elif d == 3:
        return "33333\n    3\n33333\n    3\n33333\n\n"
    elif d == 4:
        return "  44 \n 4 4 \n44444\n   4 \n   4 \n\n"
    elif d == 5:
        return "55555\n5    \n55555\n    5\n55555\n\n"
    elif d == 6:
        return "66666\n6    \n66666\n6   6\n66666\n\n"
    elif d == 7:
        return "77777\n   7 \n  7  \n 7   \n7    \n\n"
    elif d == 8:
        return "88888\n8   8\n88888\n8   8\n88888\n\n"
    else:
        return " 9999\n9   9\n 9999\n   9 \n999  \n\n"